- 跟decode way I 一样, 加法原理, 切割点时: 当下是取了 1 digit 还是 2 digits 来decode - 定义dp[i] = 前i个digits最多有多少种decode的方法. new dp[n + 1]. - 不同的情况是: 每一个partition里面, 如果有 ...
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