// For a balanced substring with one char, any length works (all chars are equal) maxlen = Math.max(maxlen, getLength(s, 'a')); // Consider 'b' and 'c' maxlen = Math ...
Given a string S and a string T, find the minimum window in S which will contain all the characters in T in complexity O(n). 1. If there is no such window in S that covers all characters in T, return ...
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